K^2+2k+1=(K+1)^2

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Solution for K^2+2k+1=(K+1)^2 equation: 



^2+2K+1=(+1)^2

We move all terms to the left:

^2+2K+1-((+1)^2)=0

We add all the numbers together, and all the variables

2K+1+^2-(1^2)=0

We add all the numbers together, and all the variables

2K=0

K=0/2

K=0

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